Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A chemist treats of bromoethane () with alcoholic potassium cyanide to make propanenitrile, (). All of the halide reacts. The nitrile is then either boiled with dilute acid, to give propanoic acid () and ammonia, or reduced to propan-1-amine (). Take every step at a yield of 100 %. Find the mass of propanenitrile, the mass of propanoic acid, the mass of ammonia formed in the hydrolysis () and the mass of propan-1-amine.
Silver cyanide gives an isocyanide and potassium cyanide gives a nitrile. A nitrile is reduced to a primary amine with one more carbon than the halide. An isocyanide is hydrolysed by acid to a primary amine and formic acid, and is reduced to a secondary amine. Nitrobenzene takes 6, 4 or 5 electrons in an acidic, neutral or alkaline medium, and each atom of zinc or tin gives 2 electrons.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Amount. .
Step 2. Nitrile. .
Step 3. Acid. . The ammonia is .
Step 4. Amine. .
Answer: , , and .
Check. The nitrile adds one carbon to the two carbons of bromoethane, so the acid and the amine both have three carbon atoms.
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