A chemist treats 5.45 g of bromoethane (109 g/mol) with alcoholic potassium cyanide to make…

A chemist treats $5.45\ \text{g}$ of bromoethane ($109\ \text{g/mol}$) with alcoholic potassium cyanide to make propanenitrile, $\text{C}_3\text{H}_5\text{N}$ ($55\ \text{g/mol}$). All of the halide reacts. The nitrile is then either boiled with dilute acid, to give propanoic acid ($74\ \text{g/mol}$) and ammonia, or reduced to propan-1-amine ($59\ \text{g/mol}$). Take every step at a yield of 100 %. Find the mass of propanenitrile, the mass of propanoic acid, the mass of ammonia formed in the hydrolysis ($17\ \text{g/mol}$) and the mass of propan-1-amine.