MediumChemistryHigh School (11–12)Coordination Compounds › Isomerism in Coordination CompoundsNumericalA-LevelIBJEE Main
A chemist has 0.0400 mol of each of two ionisation isomers, [Co(NH₃)₅Cl]SO₄ and [Co(NH₃)₅(SO₄)]Cl…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A chemist has of each of two ionisation isomers, and . She dissolves the first in water and adds excess barium chloride. She dissolves the second and adds excess silver nitrate. Use for barium sulphate and for silver chloride. What mass of precipitate forms in each case?
Need a reminder? The key ideaShow
Structural isomers have the same overall formula. Ionisation and hydrate isomers differ in what sits inside the bracket and what sits outside. Only free ions outside the bracket precipitate with silver nitrate (halide) or barium chloride (sulphate). Linkage isomers use another donor atom of an ambidentate ligand. Coordination isomers swap ligands between two complex ions.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. of each isomer.
Plan. Find the free ion in each salt, then the moles and mass of its precipitate.
Step 1. The first isomer. The sulphate is outside the bracket, so it is free. Barium chloride gives of barium sulphate. Mass: .
Step 2. The second isomer. The chloride is outside the bracket and the sulphate is inside. Silver nitrate gives of silver chloride. Mass: .
Check. Silver nitrate on the first salt gives no silver chloride, because its chloride is inside the bracket. Barium chloride on the second salt gives no barium sulphate for the same reason.
Answer: of barium sulphate and of silver chloride.
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