Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A cell makes an RNA with the sequence 5′-GGAUCCAUA-3′.
The RNA polymerase reads the template strand from 3′ to 5′ and builds the RNA from 5′ to 3′, with U in the place of T. The RNA has the sequence of the coding strand. A hnRNA loses its introns by splicing, gets a cap at the 5′ end and gets a tail of 200 to 300 adenylate residues at the 3′ end.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. (a) Pair each RNA base with a DNA base: G with C, G with C, A with T, U with A, C with G, C with G, A with T, U with A, A with T. The template, from its 3′ end, is 3′-CCTAGGTAT-5′.
Step 2. (b) The coding strand is the partner of the template. It runs the other way, and it is also the RNA with T for U: 5′-GGATCCATA-3′.
Step 3. (c) The coding strand.
Step 4. (d) The polymerase adds nucleotides to the 3′ end of the RNA, so the 5′ end was made first.
Answer: (a) 3′-CCTAGGTAT-5′; (b) 5′-GGATCCATA-3′; (c) the coding strand; (d) the 5′ end.
Check. The two DNA strands pair with each other: C with G, C with G, T with A, A with T, and so on.
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