Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A bus leaves a stop and speeds up steadily for to . It runs at that speed for , then brakes steadily and stops in the next .
Acceleration , in . It is positive when the velocity grows and negative when it falls in the positive direction.
On a distance-time (or position-time) graph the slope is the velocity. On a velocity-time graph the slope is the acceleration and the area under the line is the distance.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. (a) A line rising from to in , flat for , falling to in .
Step 2. (b) ; then ; then .
Step 3. (c) .
Answer: , , ; .
Check. As one trapezium: .
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