A bunch has 8 pea flowers. Every flower has one standard petal, two wing petals, two keel petals…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A bunch has pea flowers. Every flower has one standard petal, two wing petals, two keel petals, nine joined stamens and one free stamen. Find the number of standard petals, wing petals, keel petals, free stamens and joined stamens in the bunch.
Need a reminder? The key ideaShow
Fabaceae: zygomorphic flower, papilionaceous corolla (standard, two wings, a keel of two joined petals), ten stamens with nine joined and one free, one carpel, a legume, root nodules. Solanaceae: radial flower, united sepals and petals, five epipetalous stamens, two joined carpels, a berry or a capsule. Liliaceae: a monocot, six tepals in two whorls, six epiphyllous stamens, three joined carpels, a capsule.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Standard petals. .
Step 2. Wing petals. .
Step 3. Keel petals. .
Step 4. Free stamens. .
Step 5. Joined stamens. .
Answer: standard , wings , keel , free stamens , joined stamens .
Discussion (0)
Log in to join the discussion.
Loading…