A bulb of 7 Ω and a bulb of 11 Ω are joined in series to a 9 V battery…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A bulb of and a bulb of are joined in series to a battery. Find the current and the potential difference across each bulb.
Need a reminder? The key ideaShow
In series, the same current flows through every resistor, the potential differences add up, and
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Total. .
Step 2. Current. .
Step 3. Shares. and .
Answer: ; and .
Check. .
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