A bucket is open at the top, with top radius 15 cm and bottom radius 5 cm, and it is 24 cm high…

Step 1. The slant height. $l = \sqrt{24^2 + (15 - 5)^2}\ \text{cm} = \sqrt{676}\ \text{cm} = 26\ \text{cm}$.

Step 2. The curved surface. $\pi(15 + 5)\ \text{cm} \times 26\ \text{cm} = 520\pi\ \text{cm}^2$.

Step 3. The base. $\pi \times 5^2\ \text{cm}^2 = 25\pi\ \text{cm}^2$.

Step 4. The sheet. $520\pi + 25\pi = 545\pi\ \text{cm}^2 = 1712.2\ \text{cm}^2$.

Step 5. The volume. $\dfrac{\pi \times 24\ \text{cm}}{3}(225 + 75 + 25)\ \text{cm}^2 = 8\pi \times 325\ \text{cm}^3 = 2600\pi\ \text{cm}^3 = 8168.1\ \text{cm}^3$.

Step 6. In litres. $8168.1 \div 1000 = 8.17$ litres.