A 1.5 kg block hangs from a string wound round a uniform disc pulley of mass 4.0 kg and radius 0.15…

Step 1. (a) $a = \dfrac{1.5\ \text{kg} \times 9.8\ \text{m/s}^2}{1.5\ \text{kg} + 2.0\ \text{kg}} = 4.2\ \text{m/s}^2$.

Step 2. (b) $T = m(g - a) = 1.5\ \text{kg} \times 5.6\ \text{m/s}^2 = 8.4\ \text{N}$.

Step 3. (c) $\alpha = \dfrac{a}{R} = \dfrac{4.2\ \text{m/s}^2}{0.15\ \text{m}} = 28\ \text{rad/s}^2$.

Step 4. (d) $v = \sqrt{2 \times 4.2\ \text{m/s}^2 \times 1.2\ \text{m}} = 3.17\ \text{m/s}$.