A brass ball of radius 1.2 mm (density 8500 kg/m³) falls through glycerine (density 1260 kg/m³…

Step 1. Speed. $\dfrac{2 \times (1.2 \times 10^{-3}\ \text{m})^2}{9 \times 0.80\ \text{Pa s}} \times 7240\ \text{kg/m}^3 \times 9.8\ \text{m/s}^2 = 2.84 \times 10^{-2}\ \text{m/s}$.

Step 2. Drag. Weight less buoyancy: $\tfrac43\pi(1.2 \times 10^{-3}\ \text{m})^3 \times 7240\ \text{kg/m}^3 \times 9.8\ \text{m/s}^2 = 5.14 \times 10^{-4}\ \text{N}$.