A ball of mass 0.25 kg falls from a height of 2.2 m onto the floor.

Step 1. Speed. $v = \sqrt{2 \times 9.8\ \text{m/s}^2 \times 2.2\ \text{m}} = \sqrt{43.12\ \text{m}^2/\text{s}^2} = 6.57\ \text{m/s}$.

Step 2. Kinetic energy. $KE = mgh = 0.25\ \text{kg} \times 9.8\ \text{m/s}^2 \times 2.2\ \text{m} = 5.39\ \text{J}$.