8.20 g of sodium ethanoate (82.03 g/mol) is heated with soda lime, which gives methane and sodium…

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$8.20\ \text{g}$ of sodium ethanoate ( $82.03\ \text{g/mol}$ ) is heated with soda lime, which gives methane and sodium carbonate. Methane has a molar mass of $16.04\ \text{g/mol}$ . Take the molar volume of a gas at $273\ \text{K}$ and $1\ \text{atm}$ as $22.4\ \text{L/mol}$ . Write the equation, and find the amount of the salt, the mass of methane and the volume at $273\ \text{K}$ and $1\ \text{atm}$ .

Need a reminder? The key ideaShow

Fischer esterification is an equilibrium: $K = \dfrac{x^2}{(1 - x)(r - x)}$ for 1 mol of acid and $r$ mol of alcohol. SOCl $_2$ gives acid chlorides, LiAlH $_4$ gives alcohols, Br $_2$ with red P gives 2-bromo acids (Hell-Volhard-Zelinsky), soda lime removes one carbon, and Kolbe electrolysis doubles the alkyl group. Molar volume of a gas at 273 K and 1 atm: 22.4 L/mol.

The worked solution

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8.20 g of sodium ethanoate (82.03 g/mol) is heated with soda lime, which gives methane and sodium…

The worked solution

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