146.25 g of sodium chloride is electrolysed in brine: 2NaCl + 2H₂O → 2NaOH + Cl₂ + H₂.

Step 1. Moles of salt. $\dfrac{146.25\ \text{g}}{58.5\ \text{g/mol}} = 2.5\ \text{mol}$.

Step 2. NaOH. $2.5\ \text{mol} \times 40\ \text{g/mol} = 100\ \text{g}$.

Step 3. Chlorine. $1.25\ \text{mol} \times 71\ \text{g/mol} = 88.75\ \text{g}$.

Step 4. Hydrogen. $1.25\ \text{mol} \times 2\ \text{g/mol} = 2.5\ \text{g}$.