4.40 g of ethanal (44.05 g/mol) is warmed with an excess of methanol (32.04 g/mol) and a little dry…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
of ethanal () is warmed with an excess of methanol () and a little dry HCl. The acetal 1,1-dimethoxyethane () forms in a yield of , with one mole of water for each mole of acetal. Write the equation. What is the least mass of methanol that the reaction needs? What mass of acetal is obtained? Say why dry HCl is used.
Need a reminder? The key ideaShow
A nucleophile attacks the carbonyl carbon, the carbon changes from to , and the oxygen then takes a proton. Alkyl groups lower the positive charge and crowd the carbon, so methanal > other aldehydes > ketones. HCN gives a cyanohydrin, NaHSO a bisulphite compound, alcohols with dry HCl an acetal, and compounds a C=N compound and water.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Equation.
Step 2. Amount. .
Step 3. Methanol. Two moles for each mole of ethanal: , which is .
Step 4. Acetal. .
Step 5. Dry HCl. The reaction is an equilibrium that makes water. Water would push it back, and it would also hydrolyse the acetal. Dry conditions keep it on the acetal side.
Answer: and .
What if? Dilute aqueous acid reverses the reaction and gives back ethanal and methanol.
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