2.90 g of propanone (58.08 g/mol) is warmed with iodine and sodium hydroxide…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
of propanone () is warmed with iodine and sodium hydroxide. The equation is . The yield of iodoform () is . Find the amount of propanone, the theoretical mass of iodoform and the mass obtained. Then find the amount of iodine () used up.
Need a reminder? The key ideaShow
NaBH, LiAlH and H with a metal reduce C=O to an alcohol. Zn-Hg with conc. HCl (Clemmensen) or NHNH then KOH (Wolff-Kishner) reduce it to CH. Tollens' reagent gives 2 Ag for each aldehyde group, and Fehling's solution gives 1 CuO. The iodoform test is given by CHCO- groups and CHCH(OH)- groups.
The worked solution
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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. .
Step 2. Theory: .
Step 3. Obtained: .
Step 4. Iodine: .
Answer: , , and .
Check. Iodoform carries three iodine atoms. The other three iodine atoms go into sodium iodide.
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