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2.00 mol of an ideal gas at 310 K expands reversibly and at constant temperature from 5.00 L to…

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$2.00$ mol of an ideal gas at $310$ K expands reversibly and at constant temperature from $5.00$ L to $20.0$ L. Find $w$ , $\Delta U$ and $q$ , in kJ. Use $R = 8.314$ J K $^{-1}$ mol $^{-1}$ .

Need a reminder? The key ideaShow

Work against a constant outside pressure: $w = -p_\text{ex}\Delta V$ , with $1$ L bar $= 100$ J and $1$ L atm $= 101.3$ J. Free expansion: $w = 0$ . Reversible isothermal ideal gas: $w = -2.303\,nRT\log\dfrac{V_f}{V_i}$ , and $\Delta U = 0$ , so $q = -w$ .

The worked solution

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2.00 mol of an ideal gas at 310 K expands reversibly and at constant temperature from 5.00 L to…

The worked solution

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