A brief note on The Normal Distribution and Its Areas . Read it before a test. Try each question at the end before you open its answer.
The curve Density curve: total area 1 1 1 . The area between two values is the share of values there. Normal curve: a symmetric bell, fixed by the mean μ \mu μ and the standard deviation σ \sigma σ . The rule: about 68 % 68\% 68% , 95 % 95\% 95% and 99.7 % 99.7\% 99.7% within 1 1 1 , 2 2 2 and 3 3 3 standard deviations (exactly 0.6827 0.6827 0.6827 , 0.9545 0.9545 0.9545 and 0.9973 0.9973 0.9973 ). Areas z-score: z = x − μ σ z = \dfrac{x - \mu}{\sigma} z = σ x − μ . Below: Φ ( z ) \Phi(z) Φ ( z ) . Above: 1 − Φ ( z ) 1 - \Phi(z) 1 − Φ ( z ) . Between: Φ ( z 2 ) − Φ ( z 1 ) \Phi(z_2) - \Phi(z_1) Φ ( z 2 ) − Φ ( z 1 ) . Symmetry: Φ ( − z ) = 1 − Φ ( z ) \Phi(-z) = 1 - \Phi(z) Φ ( − z ) = 1 − Φ ( z ) . Percentile: find z z z from the share, then x = μ + z σ x = \mu + z\sigma x = μ + z σ . Python: NormalDist(mu, sigma).cdf(x) and .inv_cdf(share). When it fits Binomial counts: close to normal when n p ≥ 10 np \ge 10 n p ≥ 10 and n ( 1 − p ) ≥ 10 n(1 - p) \ge 10 n ( 1 − p ) ≥ 10 . Not normal: skewed data such as waiting times and incomes, bounded data, small counts. Checks: a histogram, the mean against the median, the 68-95 shares. Totals and averages of many independent parts tend to be normal. A worked example Masses of made-up pumpkins follow a normal curve with mean 6.0 kg 6.0\ \text{kg} 6.0 kg and standard deviation 1.5 kg 1.5\ \text{kg} 1.5 kg .
Heavier than 8.25 kg 8.25\ \text{kg} 8.25 kg . z = 8.25 − 6.0 1.5 = 1.5 z = \dfrac{8.25 - 6.0}{1.5} = 1.5 z = 1.5 8.25 − 6.0 = 1.5 , so the share is 1 − 0.9332 = 0.0668 1 - 0.9332 = 0.0668 1 − 0.9332 = 0.0668 . Between 4.5 kg 4.5\ \text{kg} 4.5 kg and 7.5 kg 7.5\ \text{kg} 7.5 kg . That is one standard deviation each way: 0.6827 0.6827 0.6827 . The lightest 5 % 5\% 5% . z ≈ − 1.6449 z \approx -1.6449 z ≈ − 1.6449 , so they weigh less than 6.0 − 1.6449 × 1.5 ≈ 3.53 kg 6.0 - 1.6449 \times 1.5 \approx 3.53\ \text{kg} 6.0 − 1.6449 × 1.5 ≈ 3.53 kg . Practice with new numbers
A program to try The program checks the worked example with statistics.NormalDist.
Run it. Which line gives the answer to step 3?
1. Change the standard deviation 1.5 to 1.0. Is the share heavier than 8.25 kg 8.25\ \text{kg} 8.25 kg larger or smaller now?
Mistakes to avoid The height of the curve read as a probability. The area to the left used for "above". The sign of z z z dropped for a value below the mean. A normal model used for skewed or bounded data. Check yourself What share of a normal distribution lies below μ − σ \mu - \sigma μ − σ ? Stuck? Show a hint Show the answerA normal distribution has μ = 30 \mu = 30 μ = 30 and σ = 5 \sigma = 5 σ = 5 . Find the z-score of 22 22 22 . Stuck? Show a hint Show the answerUse the table value Φ ( 2 ) = 0.9772 \Phi(2) = 0.9772 Φ ( 2 ) = 0.9772 to find P ( Z < − 2 ) P(Z < -2) P ( Z < − 2 ) . Stuck? Show a hint Show the answerIs B ( 40 , 0.5 ) B(40, 0.5) B ( 40 , 0.5 ) close to normal by the rule of 10 10 10 ? Stuck? Show a hint Show the answerSources OpenStax, Introductory Statistics , Chapter 6 on the normal distribution, and Chapter 7 on the central limit theorem.