A brief note on The Law of Gravitation . Read it before a test. Try each question at the end before you open its answer.
The big ideas Every object in the universe pulls every other object. The pull acts along the line joining their centres. The law: F = G m 1 m 2 r 2 F = \dfrac{Gm_1m_2}{r^2} F = r 2 G m 1 m 2 , with G = 6.67 × 10 − 11 N m 2 / kg 2 G = 6.67 \times 10^{-11}\ \text{N m}^2/\text{kg}^2 G = 6.67 × 1 0 − 11 N m 2 / kg 2 , the same everywhere. The pull grows with each mass and falls with the square of the distance between the centres. The pulls on the two objects are equal and opposite, even when one is the Earth and the other an apple. Near a planet every object falls with the same acceleration, g = G M R 2 g = \dfrac{GM}{R^2} g = R 2 GM . On the Earth g = 9.8 m/s 2 g = 9.8\ \text{m/s}^2 g = 9.8 m/s 2 . g g g gets smaller as you go higher, because you move away from the centre. The facts at a glance Change What happens to the force One mass doubled × 2 \times 2 × 2 Both masses doubled × 4 \times 4 × 4 Distance doubled × 1 4 \times \tfrac14 × 4 1 Distance three times as large × 1 9 \times \tfrac19 × 9 1
Quantity Formula or value Unit Force of gravity F = G m 1 m 2 r 2 F = \dfrac{Gm_1m_2}{r^2} F = r 2 G m 1 m 2 N G G G 6.67 × 10 − 11 6.67 \times 10^{-11} 6.67 × 1 0 − 11 N m 2 / kg 2 \text{N m}^2/\text{kg}^2 N m 2 / kg 2 g g g on a planet g = G M R 2 g = \dfrac{GM}{R^2} g = R 2 GM m/s 2 \text{m/s}^2 m/s 2 g g g on the Earth 9.8 9.8 9.8 m/s 2 \text{m/s}^2 m/s 2
A worked example Two lead spheres of 40 kg 40\ \text{kg} 40 kg and 25 kg 25\ \text{kg} 25 kg have their centres 0.5 m 0.5\ \text{m} 0.5 m apart. Find the pull between them.
The law. F = G × 40 kg × 25 kg ( 0.5 m ) 2 F = \dfrac{G \times 40\ \text{kg} \times 25\ \text{kg}}{(0.5\ \text{m})^2} F = ( 0.5 m ) 2 G × 40 kg × 25 kg , with G = 6.67 × 10 − 11 N m 2 / kg 2 G = 6.67 \times 10^{-11}\ \text{N m}^2/\text{kg}^2 G = 6.67 × 1 0 − 11 N m 2 / kg 2 . Work it out. The top is 6.67 × 10 − 8 N m 2 6.67 \times 10^{-8}\ \text{N m}^2 6.67 × 1 0 − 8 N m 2 ; divide by 0.25 m 2 0.25\ \text{m}^2 0.25 m 2 . So F = 2.67 × 10 − 7 N F = 2.67 \times 10^{-7}\ \text{N} F = 2.67 × 1 0 − 7 N , far too small to notice. Gravity is only strong when one of the masses is huge. Practice with new numbers
A program to try The program works out the pull between the spheres, then g g g on the Earth.
Read it, then run it.
Move the spheres to 1 m 1\ \text{m} 1 m apart. By how many times does the pull fall?
Mistakes to avoid Forgetting to square the distance. Twice as far gives a quarter of the pull, not a half. Measuring r r r from the surface. It runs from centre to centre: for the Earth, add its radius. 'The Earth pulls the apple harder than the apple pulls the Earth.' The pulls are equal; the apple moves more because its mass is tiny. 'Heavy objects have a bigger g g g .' g g g depends on the planet, not on the falling object. Check yourself Two bodies attract with 35 N 35\ \text{N} 35 N . The distance between them is halved. What is the new force? Stuck? Show a hint Show the answerWhy do we not feel the pull of the person sitting next to us? Stuck? Show a hint Show the answerA planet has the Earth's radius but four times its mass. What is g g g there? Stuck? Show a hint Show the answerWhere is g g g bigger, at sea level or on top of a mountain? Stuck? Show a hint Show the answerThe Earth pulls a 0.15 kg 0.15\ \text{kg} 0.15 kg apple with 1.47 N 1.47\ \text{N} 1.47 N . How hard does the apple pull the Earth? Stuck? Show a hint Show the answer