A brief note on The Frustum of a Cone . Read it before a test. Try each question at the end before you open its answer.
The shape and its measures A frustum is a cone with its top cut off by a plane parallel to the base . It has a bottom radius R R R , a top radius r r r and a height h h h . Slant height: l = h 2 + ( R − r ) 2 l = \sqrt{h^2 + (R - r)^2} l = h 2 + ( R − r ) 2 . The small cone cut off is similar to the complete cone: r R = H − h H \dfrac{r}{R} = \dfrac{H - h}{H} R r = H H − h . So H = h R R − r H = \dfrac{hR}{R - r} H = R − r h R and L = l R R − r L = \dfrac{lR}{R - r} L = R − r l R . The net of the curved surface is a ring with outer radius L L L , inner radius L − l L - l L − l and angle R L × 360 ∘ \dfrac{R}{L} \times 360^\circ L R × 36 0 ∘ . Areas and volume Curved surface: π ( R + r ) l \pi(R + r)\,l π ( R + r ) l . Total surface of a closed frustum: π ( R + r ) l + π R 2 + π r 2 \pi(R + r)\,l + \pi R^2 + \pi r^2 π ( R + r ) l + π R 2 + π r 2 . An open bucket has the curved surface and the base only. Volume: π h 3 ( R 2 + R r + r 2 ) \dfrac{\pi h}{3}(R^2 + Rr + r^2) 3 π h ( R 2 + R r + r 2 ) . Each comes from the big cone minus the small cone. With r = R r = R r = R the formulas give the cylinder. A cone cut parallel to its base: the small cone with scale f f f has f 2 f^2 f 2 of the curved surface and f 3 f^3 f 3 of the volume. A worked example A frustum has bottom radius 6 cm 6\ \text{cm} 6 cm , top radius 2 cm 2\ \text{cm} 2 cm and height 9 cm 9\ \text{cm} 9 cm . Find its volume in terms of π \pi π .
The bracket is R 2 + R r + r 2 = 36 + 12 + 4 = 52 cm 2 R^2 + Rr + r^2 = 36 + 12 + 4 = 52\ \text{cm}^2 R 2 + R r + r 2 = 36 + 12 + 4 = 52 cm 2 . The volume is π × 9 cm 3 × 52 cm 2 = 156 π cm 3 \dfrac{\pi \times 9\ \text{cm}}{3} \times 52\ \text{cm}^2 = 156\pi\ \text{cm}^3 3 π × 9 cm × 52 cm 2 = 156 π cm 3 . Practice with new numbers
A program to try The program finds the volume of a frustum by the formula and as the difference of two cones.
Run it. Do the two volumes agree?
1. Change r = 2 to r = 5. Do they still agree?
Mistakes to avoid Using the height in place of the slant height in π ( R + r ) l \pi(R + r)l π ( R + r ) l . Writing ( R + r ) 2 (R + r)^2 ( R + r ) 2 in the bracket of the volume. It is R 2 + R r + r 2 R^2 + Rr + r^2 R 2 + R r + r 2 . Counting the open end of a bucket as metal. Using the square for volumes of similar cones. Volumes go with the cube. Check yourself A frustum has radii 5 cm 5\ \text{cm} 5 cm and 2 cm 2\ \text{cm} 2 cm and height 4 cm 4\ \text{cm} 4 cm . What is its slant height? Stuck? Show a hint Show the answerFor that frustum, find the curved surface area in terms of π \pi π . Stuck? Show a hint Show the answerA small cone is cut from the top of a cone and has scale 1 3 \frac{1}{3} 3 1 . What fraction of the volume does it have? Stuck? Show a hint Show the answerA bucket is open at the top and its top is the wide end. Which circle counts as part of its surface? Stuck? Show a hint Show the answer