Photons and the photoelectric effect, the stopping potential and its graph, Bohr's levels of hydrogen and its spectral series, and the de Broglie wavelength of matter. With the usual slips and questions to check yourself.
A brief note on Modern Physics. Read it before a test. Try each question at the end before you open its answer.
The big ideas
Light comes in photons: E=hν=λhc, with hc=1240eV nm.
Photoelectric effect:KEmax=hν−ϕ=eV0. Below the threshold no electrons leave; brightness changes how many, not how fast.
Bohr's hydrogen:En=−n213.6eV (Z2 times that for an ion with one electron). A jump gives a photon of the energy difference.
Series: Lyman ends on n=1 (ultraviolet), Balmer on n=2 (visible), Paschen on n=3 (infrared).
Matter waves:λ=mvh; for an electron through V volts, λ=V1.227nm.
The facts at a glance
Photon: E=λ1240eV nm
Einstein: KEmax=hν−ϕ, eV0=KEmax
Graph of V0 against ν: slope eh, the same for every metal
Hydrogen level: En=−n213.6eV
Lines from level n: up to 2n(n−1)
De Broglie: λ=ph
A worked example
Light of 300nm falls on a metal whose work function is 3.4eV. Find the largest kinetic energy and the stopping potential. Then find the de Broglie wavelength of an electron speeded up by 81V.
The photon.300nm1240eV nm=4.13eV.
Einstein.KEmax=4.13eV−3.4eV=0.73eV, so V0=0.73V.
The electron.λ=811.227nm=0.136nm.
Practice with new numbers
A program to try
Mistakes to avoid
Thinking brighter light gives faster electrons. Only the frequency sets KEmax.
Dividing by n instead of n2 in En=−n213.6eV.
Forgetting Z2 for He+ and Li2+.
Forgetting the square root in λ=V1.227nm.
Check yourself
What is the energy of a photon of 207nm?
What is the energy of the n=3 level of He+?
Why does a dim violet light eject electrons from a metal that a bright red light cannot?
What is the de Broglie wavelength of an electron speeded up from rest by 400V?