A brief note on Long-Run Chance and the Addition Rule . Read it before a test. Try each question at the end before you open its answer.
Two ways to find a probability From data: relative frequency = times it happened tries = \dfrac{\text{times it happened}}{\text{tries}} = tries times it happened . From equal chances: P ( A ) = outcomes in A all outcomes P(A) = \dfrac{\text{outcomes in } A}{\text{all outcomes}} P ( A ) = all outcomes outcomes in A . A model: every probability is between 0 0 0 and 1 1 1 , and all of them add up to 1 1 1 . The long run Law of large numbers: the share of successes gets close to the probability as the tries grow. The band: in about 95 95 95 runs out of 100 100 100 , the share is within 2 p ( 1 − p ) / n 2\sqrt{p(1-p)/n} 2 p ( 1 − p ) / n of p p p . A fair coin: the half-width is 1 n \dfrac{1}{\sqrt{n}} n 1 . Only the share settles: the count of heads minus half does not have to shrink. Complements and the addition rule Complement: P ( not A ) = 1 − P ( A ) P(\text{not } A) = 1 - P(A) P ( not A ) = 1 − P ( A ) . Exclusive events: P ( A ∪ B ) = P ( A ) + P ( B ) P(A \cup B) = P(A) + P(B) P ( A ∪ B ) = P ( A ) + P ( B ) . Any two events: P ( A ∪ B ) = P ( A ) + P ( B ) − P ( A ∩ B ) P(A \cup B) = P(A) + P(B) - P(A \cap B) P ( A ∪ B ) = P ( A ) + P ( B ) − P ( A ∩ B ) . A worked example A made-up shop records 80 80 80 shoppers. 44 44 44 pay by card, 30 30 30 pay by phone and 14 14 14 use both on different visits.
Card or phone. 44 + 30 − 14 = 60 44 + 30 - 14 = 60 44 + 30 − 14 = 60 shoppers, so the probability is 60 80 = 0.75 \dfrac{60}{80} = 0.75 80 60 = 0.75 . Neither. 1 − 0.75 = 0.25 1 - 0.75 = 0.25 1 − 0.75 = 0.25 , which is 20 20 20 shoppers. Card only. 44 − 14 = 30 44 - 14 = 30 44 − 14 = 30 shoppers, so the probability is 30 80 = 0.375 \dfrac{30}{80} = 0.375 80 30 = 0.375 . Practice with new numbers
A program to try The program checks the worked example, and then picks a shopper at random 10000 10000 10000 times to watch the share settle.
Run it. Is the share of the 10000 10000 10000 picks close to 0.75 0.75 0.75 ?
1. Change both = 14 to both = 20. What should P(card or phone) be now? Run it to check.
Mistakes to avoid Counting the overlap twice. Subtract P ( A ∩ B ) P(A \cap B) P ( A ∩ B ) once. Expecting a short run to match the probability. Only a long run settles. Thinking results even out. The share settles, but the count does not catch up. A model that does not add up to 1 1 1 . Look for a missing outcome. Check yourself A made-up machine jammed 14 14 14 times in 350 350 350 runs. Estimate the probability of a jam. Stuck? Show a hint Show the answerA fair coin is tossed 900 900 900 times. Give the band for the share of heads. Stuck? Show a hint Show the answerP ( A ) = 0.3 P(A) = 0.3 P ( A ) = 0.3 , P ( B ) = 0.5 P(B) = 0.5 P ( B ) = 0.5 and P ( A ∩ B ) = 0.1 P(A \cap B) = 0.1 P ( A ∩ B ) = 0.1 . Find P ( A ∪ B ) P(A \cup B) P ( A ∪ B ) . Stuck? Show a hint Show the answerTwo events are mutually exclusive, with probabilities 0.25 0.25 0.25 and 0.4 0.4 0.4 . Find the probability of neither. Stuck? Show a hint Show the answerSources OpenStax, Introductory Statistics , Chapter 3, the sections on terminology, the basic rules of probability and Venn diagrams.