A brief note on Geometric Progressions and the AM-GM Inequality . Read it before a test. Try each question at the end before you open its answer.
What Formula nth term a n = a r n − 1 a_n = a r^{n - 1} a n = a r n − 1 sum of n n n terms a ( r n − 1 ) r − 1 \dfrac{a(r^n - 1)}{r - 1} r − 1 a ( r n − 1 ) , or n a na na if r = 1 r = 1 r = 1 sum to infinity a 1 − r \dfrac{a}{1 - r} 1 − r a , only if ∣ r ∣ < 1 \lvert r \rvert < 1 ∣ r ∣ < 1 geometric mean G = a b G = \sqrt{ab} G = ab
a a a , b b b , c c c are in GP exactly when b 2 = a c b^2 = ac b 2 = a c . Three numbers in GP: write them a r \dfrac{a}{r} r a , a a a , a r ar a r . n n n means between a a a and b b b : r = ( b a ) 1 n + 1 r = \left(\dfrac{b}{a}\right)^{\frac{1}{n + 1}} r = ( a b ) n + 1 1 . For positive numbers, A ≥ G A \ge G A ≥ G , with equality only when they are equal. Two numbers with means A A A and G G G are the roots of x 2 − 2 A x + G 2 = 0 x^2 - 2Ax + G^2 = 0 x 2 − 2 A x + G 2 = 0 . A worked example Find the sum of the first 6 6 6 terms of 5 , 15 , 45 , … 5, 15, 45, \ldots 5 , 15 , 45 , … , and the sum to infinity of 5 + 5 3 + 5 9 + ⋯ 5 + \tfrac{5}{3} + \tfrac{5}{9} + \cdots 5 + 3 5 + 9 5 + ⋯
Step 1. The first sum. a = 5 a = 5 a = 5 and r = 3 r = 3 r = 3 : 5 ( 3 6 − 1 ) 3 − 1 = 5 × 728 2 = 1820 \dfrac{5(3^6 - 1)}{3 - 1} = \dfrac{5 \times 728}{2} = 1820 3 − 1 5 ( 3 6 − 1 ) = 2 5 × 728 = 1820 .
Step 2. The second sum. a = 5 a = 5 a = 5 and r = 1 3 r = \tfrac{1}{3} r = 3 1 : 5 1 − 1 3 = 15 2 \dfrac{5}{1 - \tfrac{1}{3}} = \dfrac{15}{2} 1 − 3 1 5 = 2 15 .
Answer: 1820 1820 1820 and 15 2 \tfrac{15}{2} 2 15 .
Practice with new numbers
A program to try The program checks both sums of the worked example with exact fractions.
Run it. Does it find 1820 1820 1820 and f r a c 152 frac{15}{2} f r a c 15 2 ?
1. Change n to 8. Predict the new sum first.
Mistakes to avoid a r n ar^n a r n for the nth term. It is a r n − 1 ar^{n - 1} a r n − 1 . The sum formula with r = 1 r = 1 r = 1 . The sum is n a na na . A sum to infinity with ∣ r ∣ ≥ 1 |r| \ge 1 ∣ r ∣ ≥ 1 . There is none. Forgetting the way up. A bouncing ball travels each rebound twice. AM-GM with negative numbers. It needs positive numbers. Check yourself Find the 4th term of 10 , 5 , 5 2 , … 10, 5, \tfrac{5}{2}, \ldots 10 , 5 , 2 5 , … Stuck? Show a hint Show the answerFind the sum to infinity of 1 − 1 2 + 1 4 − ⋯ 1 - \tfrac{1}{2} + \tfrac{1}{4} - \cdots 1 − 2 1 + 4 1 − ⋯ Stuck? Show a hint Show the answerWrite 0. 5 ‾ 0.\overline{5} 0. 5 as a fraction. Stuck? Show a hint Show the answerFind the geometric mean of 2 2 2 and 18 18 18 . Stuck? Show a hint Show the answerFor x > 0 x > 0 x > 0 , what is the least value of x + 25 x x + \dfrac{25}{x} x + x 25 ? Stuck? Show a hint Show the answer