A brief note on Electric Charge and Coulomb's Law . Read it before a test. Try each question at the end before you open its answer.
Charge Two kinds: positive and negative. Like charges repel. Unlike charges attract. Rubbing: only electrons move. The body that gains electrons is negative. Unit: the coulomb, 1 C = 1 A s 1\ \text{C} = 1\ \text{A s} 1 C = 1 A s . e = 1.6 × 10 − 19 e = 1.6 \times 10^{-19} e = 1.6 × 1 0 − 19 C. Conductors and insulators: free electrons move in a conductor. Charge stays where it was put on an insulator. Contact: the body gets the same sign as the rod. Induction: the body gets the opposite sign, and the rod keeps its charge. Additive: add charges with their signs. Conserved: the total charge of an isolated system does not change. Quantised: Q = n e Q = ne Q = n e , with n n n a whole number. Identical metal spheres that touch share the total charge equally. Coulomb's law Force between point charges: F = k q 1 q 2 r 2 F = k\dfrac{q_1q_2}{r^2} F = k r 2 q 1 q 2 , along the line that joins them. The constant: k = 1 4 π ε 0 = 9.0 × 10 9 N m 2 / C 2 k = \dfrac{1}{4\pi\varepsilon_0} = 9.0 \times 10^9\ \text{N m}^2/\text{C}^2 k = 4 π ε 0 1 = 9.0 × 1 0 9 N m 2 / C 2 , with ε 0 = 8.85 × 10 − 12 C 2 / ( N m 2 ) \varepsilon_0 = 8.85 \times 10^{-12}\ \text{C}^2/(\text{N m}^2) ε 0 = 8.85 × 1 0 − 12 C 2 / ( N m 2 ) . Direction: the two forces are equal and opposite. Like charges repel and unlike charges attract. Distance: double r r r and the force falls to a quarter. In a medium: F = 1 K ( k q 1 q 2 r 2 ) F = \dfrac{1}{K}\left(k\dfrac{q_1q_2}{r^2}\right) F = K 1 ( k r 2 q 1 q 2 ) . For water K ≈ 80 K \approx 80 K ≈ 80 . Compared with gravity: between an electron and a proton the electric force is about 10 39 10^{39} 1 0 39 times larger. Several charges Superposition: other charges do not change the force between two charges. F ⃗ = F ⃗ 1 + F ⃗ 2 + … \vec F = \vec F_1 + \vec F_2 + \dots F = F 1 + F 2 + … On a line: choose a positive direction and add the forces with signs. In a plane: add components, then F = F x 2 + F y 2 F = \sqrt{F_x^2 + F_y^2} F = F x 2 + F y 2 . Zero force between two like charges: x d − x = q 1 q 2 \dfrac{x}{d - x} = \sqrt{\dfrac{q_1}{q_2}} d − x x = q 2 q 1 , nearer the smaller charge. A worked example A charge of + 8 μ C +8\ \mu\text{C} + 8 μ C and a charge of − 2 μ C -2\ \mu\text{C} − 2 μ C are 0.40 0.40 0.40 m apart in air. Find the force between them.
Sizes in SI units. q 1 = 8 × 10 − 6 q_1 = 8 \times 10^{-6} q 1 = 8 × 1 0 − 6 C and q 2 = 2 × 10 − 6 q_2 = 2 \times 10^{-6} q 2 = 2 × 1 0 − 6 C. The size. F = k q 1 q 2 r 2 F = \dfrac{kq_1q_2}{r^2} F = r 2 k q 1 q 2 . The top is 9.0 × 10 9 × 8 × 10 − 6 × 2 × 10 − 6 N m 2 = 0.144 N m 2 9.0 \times 10^9 \times 8 \times 10^{-6} \times 2 \times 10^{-6}\ \text{N m}^2 = 0.144\ \text{N m}^2 9.0 × 1 0 9 × 8 × 1 0 − 6 × 2 × 1 0 − 6 N m 2 = 0.144 N m 2 . The bottom is ( 0.40 m ) 2 = 0.16 m 2 (0.40\ \text{m})^2 = 0.16\ \text{m}^2 ( 0.40 m ) 2 = 0.16 m 2 . So F = 0.9 N F = 0.9\ \text{N} F = 0.9 N . The direction. The charges are unlike, so each pulls the other with 0.9 0.9 0.9 N. Practise with new numbers
Check yourself Two charges repel with a force of 20 20 20 N. They are put in a liquid with a dielectric constant of 4 4 4 , at the same distance. What is the force now? Stuck? Show a hint Show the answerHow many electrons make a charge of 5.0 5.0 5.0 nC? Stuck? Show a hint Show the answerA charge + q +q + q is placed midway between a charge + Q +Q + Q and a charge − Q -Q − Q . Which way does the net force on + q +q + q point? Stuck? Show a hint Show the answer