A brief note on Cumulative Frequency Curves . Read it before a test. Try each question at the end before you open its answer.
The two curves The less than total of a limit counts the values below it. Plot it at the upper limit . The curve rises from 0 0 0 to N N N . The more than total of a limit counts the values above it. Plot it at the lower limit . The curve falls from N N N to 0 0 0 . At every limit, less than plus more than equals N N N . The two curves cross at the height N 2 \dfrac{N}{2} 2 N . The horizontal reading of the crossing is the median. Reading the curve Median: height N 2 \dfrac{N}{2} 2 N . Lower quartile: height N 4 \dfrac{N}{4} 4 N . Upper quartile: height 3 N 4 \dfrac{3N}{4} 4 3 N . The p p p th percentile: height p 100 N \dfrac{p}{100}N 100 p N . Interquartile range: Q 3 − Q 1 Q_3 - Q_1 Q 3 − Q 1 . The number of values between two limits is the difference of the readings of the curve. A reading at height H H H is l + H − c f f × h l + \dfrac{H - cf}{f} \times h l + f H − c f × h in the class where the running total reaches H H H . Missing frequencies Call the missing frequency x x x . Write the mean, the median or the total as a formula in x x x . Solve, and check. For the median, decide the median class first, then check it. A frequency is a whole number that is not negative. Two missing frequencies need two equations. A worked example The frequencies 5 , 11 , 16 , 8 5, 11, 16, 8 5 , 11 , 16 , 8 are in the classes 0 0 0 to 20 20 20 , 20 20 20 to 40 40 40 , 40 40 40 to 60 60 60 and 60 60 60 to 80 80 80 . Find the quartiles and the interquartile range.
The running totals. 5 , 16 , 32 , 40 5, 16, 32, 40 5 , 16 , 32 , 40 , and N = 40 N = 40 N = 40 . Q 1 Q_1 Q 1 . The height is 10 10 10 , in the class 20 20 20 to 40 40 40 : Q 1 = 20 + 10 − 5 11 × 20 = 29.09 Q_1 = 20 + \dfrac{10 - 5}{11} \times 20 = 29.09 Q 1 = 20 + 11 10 − 5 × 20 = 29.09 . Q 3 Q_3 Q 3 . The height is 30 30 30 , in the class 40 40 40 to 60 60 60 : Q 3 = 40 + 30 − 16 16 × 20 = 57.5 Q_3 = 40 + \dfrac{30 - 16}{16} \times 20 = 57.5 Q 3 = 40 + 16 30 − 16 × 20 = 57.5 . The interquartile range. 57.5 − 29.09 = 28.41 57.5 - 29.09 = 28.41 57.5 − 29.09 = 28.41 . Practice with new numbers
A program to try The program reads the two quartiles and the median from the curve of the table.
Run it. Do you get the quartiles above?
1. Change the first frequency from 5 to 15. Which of the three readings changes most?
Mistakes to avoid Plotting at the class mark instead of the upper limit. Mixing up the two types. Less than rises. More than falls. Using N 4 \dfrac{N}{4} 4 N for the upper quartile. It is at 3 N 4 \dfrac{3N}{4} 4 3 N . Forgetting that N N N contains the missing frequency. Check yourself A table has N = 60 N = 60 N = 60 . At what height do the two curves cross? Stuck? Show a hint Show the answerThe quartiles of a set are 14 14 14 and 31 31 31 . What is the interquartile range? Stuck? Show a hint Show the answerThe curve is at height 9 9 9 at 20 20 20 and at height 24 24 24 at 50 50 50 . How many values lie between 20 20 20 and 50 50 50 ? Stuck? Show a hint Show the answerThe mean of a table with a missing frequency x x x is given. What is the first thing to write? Stuck? Show a hint Show the answerSources NCERT, Mathematics for Class 10, the chapter Statistics. OpenStax, Introductory Statistics, Chapter 2 Descriptive Statistics.