A brief note on Coordinates of a Point in Space . Read it before a test. Try each question at the end before you open its answer.
Axes, planes and octants Axes: three perpendicular lines through the origin O ( 0 , 0 , 0 ) O(0, 0, 0) O ( 0 , 0 , 0 ) , in the right-handed order x x x , y y y , z z z . Coordinate planes: x y xy x y -plane ( z = 0 z = 0 z = 0 ), y z yz y z -plane ( x = 0 x = 0 x = 0 ), z x zx z x -plane ( y = 0 y = 0 y = 0 ). On an axis: two coordinates are zero. In a plane: one coordinate is zero. Octants: eight, decided by the signs of ( x , y , z ) (x, y, z) ( x , y , z ) . A point with a zero coordinate is in no octant. Feet and images Foot on a plane: make the coordinate perpendicular to the plane zero. Foot on an axis: keep only that axis's coordinate. Image in a plane: change one sign. Image in an axis: change two signs. Image in the origin: change all three. Midpoint rule: the foot is the midpoint of the point and its image. Distances of P ( x , y , z ) P(x, y, z) P ( x , y , z ) From the origin: x 2 + y 2 + z 2 \sqrt{x^2 + y^2 + z^2} x 2 + y 2 + z 2 . From the axes: y 2 + z 2 \sqrt{y^2 + z^2} y 2 + z 2 , x 2 + z 2 \sqrt{x^2 + z^2} x 2 + z 2 , x 2 + y 2 \sqrt{x^2 + y^2} x 2 + y 2 . From the planes: ∣ z ∣ |z| ∣ z ∣ , ∣ x ∣ |x| ∣ x ∣ , ∣ y ∣ |y| ∣ y ∣ . From the plane z = k z = k z = k : ∣ z − k ∣ |z - k| ∣ z − k ∣ . A worked example Find the image of P ( 4 , − 3 , 12 ) P(4, -3, 12) P ( 4 , − 3 , 12 ) in the y y y -axis and the distance of P P P from the z z z -axis.
Image. The y y y -axis keeps y y y and changes the other two signs: ( − 4 , − 3 , − 12 ) (-4, -3, -12) ( − 4 , − 3 , − 12 ) . Distance. 4 2 + ( − 3 ) 2 = 5 \sqrt{4^2 + (-3)^2} = 5 4 2 + ( − 3 ) 2 = 5 . Practice with new numbers
A program to try The program works out the main results for one point.
Read it first. Then run it. Do the results agree with the rules above?
1. Change the point to x, y, z = 6, -2, 9. Which distance is the smallest?
Mistakes to avoid Swapping the order of x x x , y y y , z z z . Changing too many signs in an image. A plane changes one, an axis changes two. Using all three squares for the distance from an axis. Leave out the coordinate along the axis. Giving an octant to a point with a zero coordinate. Check yourself Write the foot of the perpendicular from ( 5 , − 2 , 8 ) (5, -2, 8) ( 5 , − 2 , 8 ) to the z x zx z x -plane. Stuck? Show a hint Show the answerWrite the image of ( 5 , − 2 , 8 ) (5, -2, 8) ( 5 , − 2 , 8 ) in the z z z -axis. Stuck? Show a hint Show the answerFind the distance of ( 2 , 3 , 6 ) (2, 3, 6) ( 2 , 3 , 6 ) from the origin. Stuck? Show a hint Show the answerIn which octant is ( − 1 , 3 , − 7 ) (-1, 3, -7) ( − 1 , 3 , − 7 ) ? Stuck? Show a hint Show the answerFind the distance of ( 3 , 5 , 4 ) (3, 5, 4) ( 3 , 5 , 4 ) from the plane z = 9 z = 9 z = 9 . Stuck? Show a hint Show the answerSources NCERT, Mathematics Textbook for Class XI, the chapter Introduction to Three Dimensional Geometry. OpenStax, Calculus Volume 3 , Chapter 2, section 2.2 on vectors in three dimensions.