The force on a wire at different angles

A wire $0.15\ \text{m}$ long carries $6\ \text{A}$ in a field of $0.25\ \text{T}$. You will make the program find the largest force on it, the force when it makes $45^\circ$ with the field, and the angle below $90^\circ$ at which the force is half the largest. Then it draws the force against the angle.

The idea. $F = BIL\sin\theta$, where $\theta$ is the angle between the wire and the field.

Your tasks.

1. Find F_max, the force when the wire is at right angles to the field.
2. Find F45, the force at $45^\circ$.
3. Find half_angle, the angle in degrees, below $90^\circ$, at which the force is half of F_max.