Heat against current

A $15\ \Omega$ heater coil carries different currents for $30\ \text{s}$. You will make the program find the heat for seven currents, check what doubling the current does, and find the current that gives $2700\ \text{J}$. Then it draws heat against current.

The idea. $H = I^2 R t$.

Your tasks.

1. Inside the loop, work out H, the heat for the current I.
2. Find times, the heat at $2\ \text{A}$ divided by the heat at $1\ \text{A}$.
3. Find I27, the current that gives $2700\ \text{J}$ in the same coil and time.