In (a+b)n the terms rise and then fall. The ratio TrTr+1=rn−r+1⋅ab shows where the peak is. Work out m=a+b(n+1)b. The greatest term is Tk+1, where k is the whole number part of m. If m is a whole number, Tm and Tm+1 tie. The greatest coefficient is the same rule with x=1.
This is the first lesson of Binomial Theorem: Advanced Problem Set, free for everyone to read.
When the terms rise and then fall
Put x=2 in (1+x)9. The ten terms are 1, 18, 144, 672, 2016, 4032, 5376, 4608, 2304 and 512. They climb to a peak at the seventh term and then fall away.
Which term is the peak? For n=9 you can list them all. For n=99 you cannot. A short rule finds the peak at once. It comes from comparing each term with the one before it.
Two graphs side by side for the expansion of (1 + x) to the power 9 with x = 2. On the left, ten bars show the terms 1, 18, 144, 672, 2016, 4032, 5376, 4608, 2304 and 512, rising to a peak at the seventh term, which is marked as the greatest. On the right, the ratio of each term to the one before it falls from 18 on the left down to 0.22. A dashed line at ratio 1 is crossed just after the seventh term, where the ratio drops from 1.33 to 0.86.
The ratio of neighbouring terms
In (a+b)n the term Tr+1 is nCran−rbr. Divide it by the term before it:
The next term is at least as big when this ratio is at least 1. That happens exactly when
(n−r+1)b≥ra,that is,r≤a+b(n+1)b.
Call the right side m. Three things follow.
For r<m, each term is bigger than the one before it.
For r>m, each term is smaller than the one before it.
For r=m, which needs m to be a whole number, two neighbouring terms are equal.
The rule. Take a and b positive and work out m=a+b(n+1)b.
If m is not a whole number, the greatest term is Tk+1, where k is the whole number part of m.
If m is a whole number, the terms Tm and Tm+1 are equal, and both are the greatest.
Example 1. For (1+x)9 with x=2, take a=1 and b=2. Then m=310×2=6.67, so k=6. The greatest term is T7=9C626=84×64=5376. This agrees with the list.
Example 2. Find the greatest term of (2+3x)11 when x=54. The second part of the bracket is b=3x=2.4 and a=2. So m=2+2.412×2.4=6.55. The greatest term is T7.
Example 3 (a tie). Find the greatest term of (3+x)11 when x=1. Here a=3 and b=1, so m=412×1=3, a whole number. The terms T3 and T4 are equal and greatest:
In (a−b)n the signs of the terms alternate. When a question asks for the greatest numerical term, signs do not matter. Use the size of b in the rule and ignore its sign.
The greatest coefficient
The coefficient of xr in (a+bx)n is nCran−rbr. This is the term Tr+1 of (a+b)n. So the greatest coefficient comes from the same rule, with x=1.
For (1+x)n we have a=b=1, so m=2n+1.
If n is even, m is not a whole number. The greatest coefficient is the middle one, nCn/2.
If n is odd, m is a whole number. Two middle coefficients tie: nC(n−1)/2=nC(n+1)/2.
Example 4. The greatest coefficient of (1+x)12 is 12C6=924. For (1+x)13 the two middle coefficients are 13C6=13C7=1716.
The greatest term depends on x. The greatest coefficient does not. Do not mix the two questions up.
Practise with new numbers
Try it in Python
The program finds the greatest term in two ways: by trying every term, and by the ratio rule. It uses exact fractions, so a tie is never hidden by rounding.
Common mistakes
Using the whole number part as the term number. The greatest term is Tk+1, not Tk.
Missing a tie. If m is a whole number, two terms are greatest, not one.
Swapping a and b. The number that comes with x is b. Swapping them moves the peak to the wrong side.
Mixing the greatest term with the greatest coefficient. Only the term depends on x.
Keeping the sign of b. For the greatest numerical term of (a−b)n, use the size of b.
Remember these
TrTr+1=rn−r+1⋅ab.
With m=a+b(n+1)b, the greatest term is Tk+1 for k the whole number part of m, and Tm=Tm+1 when m is a whole number.
The greatest coefficient of (a+bx)n is found with x=1.
Check yourself
Try each one on your own first. If you are stuck, open a hint. Then check with Show the answer.
Which term is the greatest in (1+x)14 when x=3?
What is the greatest coefficient in (1+x)11?
In (5+2x)13 put x=1. Which terms are the greatest?
Which coefficient is the greatest in (1+x)8?
Liked this lesson? There is more
Binomial Theorem: Advanced Problem Set is a Standard course. It adds 2 more lessons, practice and tests on top of the free chapter.
11Problems2Python Labs1Question Set1Mock Test
Coefficients in products and trinomials: To find the coefficient of xk
in a product, multiply the expansions term by term and collect every pair of powers that add up to
k
. For
(1+x)m(1+x)n=(1+x)m+n
this gives Vandermonde's identity, and with
m=n
it gives
∑(nCr)2=2nCn
. For
(1+x+x2)n
, treat
x2
as a part on its own and sum over how often it is chosen.
Sums of series with binomial coefficients: Many sums with binomial coefficients follow from one identity, rnCr=nn−1Cr−1, or from differentiating or integrating the expansion of (1+x)n. They give ∑rnCr=n2n−1, ∑r2nCr=n(n+1)2n−2 and ∑r+1nCr=n+12n+1−1. For an index that is not a whole number the series never stops and works for ∣x∣<1.